FOOTBALL: Jamaica set to take on US for place in Under-17 World Cup
Jamaica's under-17 football team will play the United States of America (USA) in the second play-off game in the CONCACAF championships in Honduras on Sunday.
The teams will do battle at 5 p.m Jamaica time in San Pedro Sula.
In their last game on Wednesday, Jamaica beat the US 1-nil.
This game is a must win for the Junior Reggae Boys if they are to make it to their third World Cup after qualifying in 1999 and 2011.
At the end of the group stage all four play-off teams the United States, Jamaica, Canada and Costa Rica were tied on ten points.
The rule states that in order to determine which team plays the other in the play-offs, the greater goal difference concept will be applied.
In this case, the United States finished with the best goal difference of +9 so they will be seeded as number one.
Costa Rica is next with a +8 goal difference so they are seeded number two, while Jamaica and Canada ended with identical goal difference of +4.
Because Jamaica and Canada are tied on goal difference, the greater number of goals scored in all the group matches will be applied.
However, Canada scored more goals than Jamaica, making it the third seeded team and Jamaica, the fourth.
Also, according to the rules, the number one seeded team will play the fourth seeded team, while the second seeded team plays the third seeded team.
As a result, Jamaica will play the United States, while Costa Rica plays Canada.
The game between Costa Rica and Canada will kick-off at 2 p.m Jamaica time, while the championship encounter between the two top teams from Groups A and B, which consists of Honduras and Mexico will take place at 8 p.m Jamaica time.